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Yolk

Version 1.0 | Wiki entry @ esolangs.org | See also: PixleyExanoke


Yolk is a programming language (or computational calculus) with a very small meta-circular definition.

A Yolk program consists of an S-expression. This gives the body of a function which takes an S-expression as its argument and which evaluates to an S-expression.

In this context, an S-expression is an atom or a list of S-expressions.

An atom is one of the following seven atomic symbols: ifeq, quote, head, tail, cons, arg, or self.

Basic Semantics

-> Tests for functionality "Evaluate Yolk program"

(quote A) evaluates to A. (It does not evaluate A.)

| (quote cons)
= cons

| (quote (cons (head cons tail) cons))
= (cons (head cons tail) cons)

(head A) evaluates A to a list and itself evaluates to first element of the list.

| (head (quote (cons tail tail)))
= cons

If A is not a list, (head A), crashes.

| (head (quote head))
?

(tail A) evaluates A to a list and itself evaluates to everything except the first element of the list.

| (tail (quote (cons head head)))
= (head head)

If A is not a list, (tail A) crashes.

| (tail (quote tail))
?

(cons A B) evaluates A to a S-expression and B to a list, and evaluates to a list which is the same as B except it has an extra element on the front, B.

| (cons (quote quote) (quote (head tail cons)))
= (quote head tail cons)

(ifeq A B C D) evaluates A and B; if they evaluate to the same atom then this form evaluates to what C evaluates to, otherwise it evaluates to what D evaluates to.

| (ifeq (quote head) (quote head) (quote cons) (quote self))
= cons

| (ifeq (quote head) (quote tail) (quote cons) (quote self))
= self

Advanced semantics

arg evaluates to the argument of the current program-function.

| arg
+ ifeq
= ifeq

| (tail arg)
+ (ifeq ifeq (ifeq ifeq))
= (ifeq (ifeq ifeq))

(self A) evaluates A to an S-expression, then evaluates the main program-function with that as the argument, and evaluates to the result of that.

| (ifeq (head arg) (quote cons) arg (self (tail arg)))
+ (head head cons tail tail)
= (cons tail tail)

Meta-circular Interpreter

Preliminary Sketch

I believe it is possible to write a meta-circular interpreter for Yolk.

We'll start with a sketch of it, which is not a full interpreter but which gets the basic idea across. The sketch looks like this:

(ifeq arg (quote arg)
    arg
    (ifeq (head arg) (quote head)
        (head (self (head (tail arg))))
        (ifeq (head arg) (quote tail)
            (tail (self (head (tail arg))))
            (ifeq (head arg) (quote cons)
                (cons (self (head (tail arg))) (self (head (tail (tail arg)))))
                (ifeq (head arg) (quote quote)
                    (head (tail arg))
                    (ifeq (head arg) (quote ifeq)
                        (ifeq (self (head (tail arg)))
                            (self (head (tail (tail arg))))
                            (self (head (tail (tail (tail arg)))))
                            (self (head (tail (tail (tail (tail arg)))))))
                        (ifeq (head arg) (quote self)
                            (self (self (head (tail arg))))
                            (ifeq))))))))

The (ifeq) at the end there is just there to trigger a runtime error if things go badly.

We test this meta-circular interpreter on the previous illustrations of the basic semantics as follows. The interpreter itself is sourced from a file to reduce repetition in this document.

-> Tests for functionality "Evaluate Yolk program with MCI Sketch"

| (quote cons)
= cons

| (quote (cons (head cons tail) cons))
= (cons (head cons tail) cons)

| (head (quote (cons tail tail)))
= cons

| (head (quote head))
?

| (tail (quote (cons head head)))
= (head head)

| (tail (quote tail))
?

| (cons (quote quote) (quote (head tail cons)))
= (quote head tail cons)

| (ifeq (quote head) (quote head) (quote cons) (quote self))
= cons

| (ifeq (quote head) (quote tail) (quote cons) (quote self))
= self

With Input

-> Tests for functionality "Evaluate Yolk program with MCI with arg"

However, there is a small problem. Where does this interpreter get its input from, for arg?

Instead of having the input to the MCI just be the program to be interpreted, it must be extended: a 2-element list where the first element is the program and the second is the input.

In our first step towards doing this, we will just package the program and its input into this list, but still ignore the input. We change the MCI to handle this format by

  • replacing arg, where we read it, with (head arg), and
  • replacing arg, where we evaluate to it, with (head (tail arg)), and
  • replacing the modified arg, where we pass it to self, e.g. (self (head (tail arg))), with (cons (head (tail (head arg))) (tail arg))

And we get:

(ifeq (head arg) (quote arg)
    (head (tail arg))
    (ifeq (head (head arg)) (quote head)
        (head (self (cons (head (tail (head arg))) (tail arg))))
        (ifeq (head (head arg)) (quote tail)
            (tail (self (cons (head (tail (head arg))) (tail arg))))
            (ifeq (head (head arg)) (quote cons)
                (cons (self (cons (head (tail (head arg))) (tail arg))) (self (cons (head (tail (tail (head arg)))) (tail arg))))
                (ifeq (head (head arg)) (quote quote)
                    (head (tail (head arg)))
                    (ifeq (head (head arg)) (quote ifeq)
                        (ifeq (self (cons (head (tail (head arg))) (tail arg)))
                              (self (cons (head (tail (tail (head arg)))) (tail arg)))
                              (self (cons (head (tail (tail (tail (head arg))))) (tail arg)))
                              (self (cons (head (tail (tail (tail (tail (head arg)))))) (tail arg))))
                        (ifeq (head (head arg)) (quote self)
                            (self (self (head (tail arg))))
                            (ifeq))))))))

Now we test it.

quote in MCI.

| ((quote ifeq) cons)
= ifeq

| ((quote (ifeq (head ifeq tail) ifeq)) cons)
= (ifeq (head ifeq tail) ifeq)

head in MCI.

| ((head (quote (ifeq tail tail))) cons)
= ifeq

tail in MCI.

| ((tail (quote (cons head head))) cons)
= (head head)

cons in MCI.

| ((cons (quote quote) (quote (head tail ifeq))) ifeq)
= (quote head tail ifeq)

ifeq in MCI.

| ((ifeq (quote head) (quote head) (quote cons) (quote self)) ifeq)
= cons

| ((ifeq (quote head) (quote tail) (quote cons) (quote self)) ifeq)
= self

arg in MCI.

| (arg ifeq)
= ifeq

| ((tail arg) (ifeq ifeq (ifeq ifeq)))
= (ifeq (ifeq ifeq))

With Recursion

-> Tests for functionality "Evaluate Yolk program"

Now the final stroke — fix the implementation of self. This is kind of tricky.

In the MCI, self is used for recursively interpreting parts of the "target program", i.e. the program given in the head of the arg.

In the program being interpreted, self is used for recursing that program.

So, we evaluate the first argument to a value:

(self (cons (head (tail (head arg))) (tail arg)))

Then we want to evaluate the target program, all of it, on that value.

But wait!

We don't have a way to evaluate the entire target program! We don't even have the entire target program! We'll have to keep a copy around, so instead of a 2-element list, we'll need a 3-element list (I knew that.)

| (ifeq (head arg) (quote arg)
|     (head (tail (tail arg)))
|     (ifeq (head (head arg)) (quote head)
|         (head (self (cons (head (tail (head arg))) (tail arg))))
|         (ifeq (head (head arg)) (quote tail)
|             (tail (self (cons (head (tail (head arg))) (tail arg))))
|             (ifeq (head (head arg)) (quote cons)
|                 (cons (self (cons (head (tail (head arg))) (tail arg))) (self (cons (head (tail (tail (head arg)))) (tail arg))))
|                 (ifeq (head (head arg)) (quote quote)
|                     (head (tail (head arg)))
|                     (ifeq (head (head arg)) (quote ifeq)
|                         (ifeq (self (cons (head (tail (head arg))) (tail arg)))
|                               (self (cons (head (tail (tail (head arg)))) (tail arg)))
|                               (self (cons (head (tail (tail (tail (head arg))))) (tail arg)))
|                               (self (cons (head (tail (tail (tail (tail (head arg)))))) (tail arg))))
|                         (ifeq (head (head arg)) (quote self)
|                             (self (self (head (tail arg))))
|                             (ifeq))))))))
+ (
+   (ifeq arg (quote tail) (quote cons) (quote self))
+   (ifeq arg (quote tail) (quote cons) (quote self))
+   tail
+ )
= cons

| (ifeq (head arg) (quote arg)
|     (head (tail (tail arg)))
|     (ifeq (head (head arg)) (quote head)
|         (head (self (cons (head (tail (head arg))) (tail arg))))
|         (ifeq (head (head arg)) (quote tail)
|             (tail (self (cons (head (tail (head arg))) (tail arg))))
|             (ifeq (head (head arg)) (quote cons)
|                 (cons (self (cons (head (tail (head arg))) (tail arg))) (self (cons (head (tail (tail (head arg)))) (tail arg))))
|                 (ifeq (head (head arg)) (quote quote)
|                     (head (tail (head arg)))
|                     (ifeq (head (head arg)) (quote ifeq)
|                         (ifeq (self (cons (head (tail (head arg))) (tail arg)))
|                               (self (cons (head (tail (tail (head arg)))) (tail arg)))
|                               (self (cons (head (tail (tail (tail (head arg))))) (tail arg)))
|                               (self (cons (head (tail (tail (tail (tail (head arg)))))) (tail arg))))
|                         (ifeq (head (head arg)) (quote self)
|                             (self (self (head (tail arg))))
|                             (ifeq))))))))
+ (
+   (ifeq arg (quote tail) (quote cons) (quote self))
+   (ifeq arg (quote tail) (quote cons) (quote self))
+   head
+ )
= self

We'll also need some way to evaluate that entire client program. Well, we have ourselves, the MCI, so that should be OK. ...right? Let's try again.

We evaluate the first argument to a value:

let val = (self (cons (head (tail (head arg))) (tail arg)))

Then we get the target program:

let pgm = (head (tail arg))

Then we evaluate the target program, all of it, on that value.

(self (list pgm pgm val))

Of course we don't have list so we say

(self (cons pgm (cons pgm (cons val ()))))

Nor do we have () so

(self (cons pgm (cons pgm (cons val (tail (quote (tail)))))))

Nor do we have let so

(self (cons (head (tail arg))
        (cons (head (tail arg))
          (cons (self (cons (head (tail (head arg))) (tail arg))) (tail (quote (tail)))))))

And we hold our breath and:

| (ifeq (head arg) (quote arg)
|     (head (tail (tail arg)))
|     (ifeq (head (head arg)) (quote head)
|         (head (self (cons (head (tail (head arg))) (tail arg))))
|         (ifeq (head (head arg)) (quote tail)
|             (tail (self (cons (head (tail (head arg))) (tail arg))))
|             (ifeq (head (head arg)) (quote cons)
|                 (cons (self (cons (head (tail (head arg))) (tail arg))) (self (cons (head (tail (tail (head arg)))) (tail arg))))
|                 (ifeq (head (head arg)) (quote quote)
|                     (head (tail (head arg)))
|                     (ifeq (head (head arg)) (quote ifeq)
|                         (ifeq (self (cons (head (tail (head arg))) (tail arg)))
|                               (self (cons (head (tail (tail (head arg)))) (tail arg)))
|                               (self (cons (head (tail (tail (tail (head arg))))) (tail arg)))
|                               (self (cons (head (tail (tail (tail (tail (head arg)))))) (tail arg))))
|                         (ifeq (head (head arg)) (quote self)
|                             (self (cons (head (tail arg))
|                                     (cons (head (tail arg))
|                                       (cons (self (cons (head (tail (head arg))) (tail arg))) (tail (quote (tail)))))))
|                             (ifeq))))))))
+ (
+   (ifeq (head arg) (quote ifeq) arg (self (tail arg)))
+   (ifeq (head arg) (quote ifeq) arg (self (tail arg)))
+   (head head ifeq tail tail)
+ )
= (ifeq tail tail)

Huzzah! Now we test all the things again...

-> Tests for functionality "Evaluate Yolk program with MCI"

(quote A) evaluates to A. (It does not evaluate A.)

| ((quote ifeq) (quote ifeq) cons)
= ifeq

| ((quote (cons (head cons tail) cons)) (quote (cons (head cons tail) cons)) ifeq)
= (cons (head cons tail) cons)

(head A) evaluates A to a list and itself evaluates to first element of the list.

| ((head (quote (cons tail tail))) (head (quote (cons tail tail))) ifeq)
= cons

If A is not a list, (head A) crashes.

| ((head (quote head)) (head (quote head)) cons)
?

(tail A) evaluates A to a list and itself evaluates to everything except the first element of the list.

| ((tail (quote (cons head head))) (tail (quote (cons head head))) ifeq)
= (head head)

If A is not a list, (tail A) crashes.

| ((tail (quote tail)) (tail (quote tail)) ifeq)
?

(cons A B) evaluates A to a S-expression and B to a list, and evaluates to a list which is the same as B except it has an extra element on the front, B.

| ((cons (quote quote) (quote (head tail ifeq))) (cons (quote quote) (quote (head tail ifeq))) ifeq)
= (quote head tail ifeq)

(ifeq A B C D) evaluates A and B; if they evaluate to the same atom then this form evaluates to what C evaluates to, otherwise it evaluates to what D evaluates to.

| ((ifeq (quote head) (quote head) (quote cons) (quote self))
|  (ifeq (quote head) (quote head) (quote cons) (quote self)) tail)
= cons

| ((ifeq (quote head) (quote tail) (quote cons) (quote self))
|  (ifeq (quote head) (quote tail) (quote cons) (quote self)) tail)
= self

arg evaluates to the argument of the current program-function.

| (arg arg ifeq)
= ifeq

| ((tail arg) (tail arg) (ifeq ifeq (ifeq ifeq)))
= (ifeq (ifeq ifeq))

(self A) evaluates A to an S-expression, then evaluates the main program-function with that as the argument, and evaluates to the result of that.

| ((ifeq (head arg) (quote ifeq) arg (self (tail arg)))
|  (ifeq (head arg) (quote ifeq) arg (self (tail arg)))
|  (head head ifeq tail tail))
= (ifeq tail tail)

Discussion

Comparison to Pixley

Yolk is quite similar to Pixley. The main differences between Pixley and Yolk are:

  • Yolk is not a subset of R5RS Scheme
  • Yolk was designed in a completely different fashion

In the first version of Yolk, if and eq were different forms. I wrote a meta-circular interpreter with that version, and measured it using stats.scm from the Pixley distribution:

Cons cells: 296
Symbol instances: 169
Unique symbols: 8 (cons self tail quote arg head eq if)

Then I realized that the first argument of if was always an eq, so merged them into ifeq, and that the MCI could be simplified a tiny bit for the error case, and that version is what is presented here. It measures out to be:

Cons cells: 255
Symbol instances: 146
Unique symbols: 7 (cons self tail quote arg head ifeq)

I then noticed that the second argument to if was always a quote, but realized, when trying to change it so that it did not evaluate its second argument, that it would no longer be possible to write an MCI in the resulting language (explaining why this is, is left as an exercise for the reader.)

For comparison, the latest version of pixley.pix, as of this writing, has

Cons cells: 684
Symbol instances: 413
Unique symbols: 54

Since Yolk is very similar to Pixley, but has a much smaller meta-circular definition, an argument could definitely be made that its name should be Hooterville — but that's not such a great name for a programming language.

On the other hand, the Yolk MCI has a less interesting (IMO) depiction as nested rectangles a la Pixley. That is not to say there isn't some possible graphical depiction that makes the Yolk MCI look pretty, of course.

Computational class

Yolk is almost certainly Turing-complete. That, in itself, is not terribly interesting; what is more interesting is how we can come to that conclusion without the usual devices (giving a map from Yolk programs to Turing machines, or implementing a universal Turing machine in Yolk.)

Yolk came about from my interest in whether there are any universal computational classes which are not Turing-complete. "Universal" in this sense means something like, if M is in class C and M can simulate any other member of class C then M is universal.

We know that there is a universal Turing machine. We also know that there is no universal primitive recursive function. (There is a total function which can simulate any PR function, but that function isn't itself PR.)

And we haven't yet found a computational class that is contained in PR that is universal; they all admit to various diagonalizations and pumping lemmas and such, and the function that can simulate any member of C is always, it seems, somewhere outside C.

But are there any classes between PR and RE (the class of Turing machines) that are universal? It seems likely.

In fact, R (the class of Turing machines which always halt) qualifies in some sense: if I always give a UTM only descriptions of TMs that always halt, then that UTM always halts. (Of course, that doesn't address the question of how that UTM would prevent itself from trying to simulate a TM that doesn't halt if it were given one.)

In a similar vein, it seems possible that linear-bounded automata might be universal: if it takes a UTM at most (say) 18 steps to simulate one TM transition, then, given a description of a linear-bounded TM on input, the UTM's run time should bounded linearly too. (Well, maybe. The input on which the bounds are based is now (data+machine_description) instead of just (data)... anyway I haven't thought about it very much and it is more or less a distraction from my main point.)

The thing is that PR and RE both have simple, "syntactic" definitions. You can tell a PR computation or a RE computation just from its surface structure. But every class between them has a more complex, "semantic" definition. You need some extra machinery to tell if the machine being simulated really belongs to the class or not — you need to prove it always halts, or prove that it finishes within a linear bound of its input, or whatnot.

Yolk's meta-circular interpreter can interpret itself, and, because it is written in a general way, it can interpret any other Yolk program, too, making it a universal Yolk interpreter. Yet it has none of this extra machinery that would be required for it to be above PR yet below RE. So the functions it can interpret must be all of those in RE; i.e. Yolk is Turing-complete.

THAT IS, OF COURSE, NOT A PROOF.

But on the other hand you can look at the Yolk instructions and probably satisfy yourself that it would not be difficult to write a Tag machine in Yolk. It can locate data (arg, head, tail, quote), it can make decisions based on that data (ifeq), and it can repeat this process with different data (self).

In fact, the interesting thing is cons.

cons

We can, in fact, re-write the initial sketch of the self-interpreter without handling cons at all, because cons is only used in the definition of cons:

(ifeq arg (quote arg)
    arg
    (ifeq (head arg) (quote head)
        (head (self (head (tail arg))))
        (ifeq (head arg) (quote tail)
            (tail (self (head (tail arg))))
            (ifeq (head arg) (quote quote)
                (head (tail arg))
                (ifeq (head arg) (quote ifeq)
                    (ifeq (self (head (tail arg)))
                        (self (head (tail (tail arg))))
                        (self (head (tail (tail (tail arg)))))
                        (self (head (tail (tail (tail (tail arg)))))))
                    (ifeq (head arg) (quote self)
                        (self (self (head (tail arg))))
                        (ifeq))))))))

And you'd think, maybe, this can interpret itself. And, maybe, that because it works on smaller and smaller data each time, it is primitive recursive (a la Exanoke.) Except, no. The definition of self in the sketch is wrong, really quite wrong. And to fix it, you need to be able to hold multiple data in arg, and take it apart to find the code vs. the real data, and put it back together again — and to put it back together again, you need cons.

Or something like cons, obviously; I played with various variations but realized they all allow you to "grow" an S-expression.

Now, maybe I just didn't play with them enough. Maybe we can define some sort of cons that imposes some sort of restriction on its result not being "bigger" than its input, except when used a certain way, somehow, in self especially, so that... it all works out and it's universal but it's not Turing-complete.

But I would be willing to bet that the meta-circular interpreter for that, even if it exists, would be quite a bit larger than this.

(Happy Happy)!
Chris Pressey
London, UK
August 24th, 2014