Add --stream-name-only option to `list` command.
Chris Pressey
4 years ago
| 46 | 46 |
def list_(router, options):
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| 47 | 47 |
for stream_name, stream in router.items():
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| 48 | 48 |
if os.path.isdir(stream['from']) and os.path.isdir(stream['to']):
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| 49 | |
print("{}: {} => {}".format(stream_name, stream['from'], stream['to']))
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|
49 |
if options.stream_name_only:
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|
50 |
print(stream_name)
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|
51 |
else:
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|
52 |
print("{}: {} => {}".format(stream_name, stream['from'], stream['to']))
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| 50 | 53 |
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| 51 | 54 |
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| 52 | 55 |
def sync(router, options):
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| 145 | 148 |
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| 146 | 149 |
# - - - - list - - - -
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| 147 | 150 |
parser_list = subparsers.add_parser('list', help='List available sync streams')
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|
151 |
parser_list.add_argument('--stream-name-only', default=False, action='store_true',
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|
152 |
help='Output only the names of the available streams'
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|
153 |
)
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| 148 | 154 |
parser_list.set_defaults(func=list_)
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| 149 | 155 |
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| 150 | 156 |
# - - - - sync - - - -
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